Is PT cl4 2 a square planar?
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Is PT cl4 2 a square planar?
Oxidation of Pt in this complex is +2 thus, The four chlorine atom filled the empty orbital. The strong field splitting breaks the degeneracy of dx2- y2 and dz2 orbital. Hence stabilizes the square planer arrangement more than tetrahedral thus it should be square planar.
Why NiCl4 is square planar while NiCl4 is tetrahedral?
Explain on the basis of valence bond theory that [Ni(CN)4]2– ion with square planar is diamagnetic and the [NiCl4]2– ion with tetrahedral geometry is paramagnetic. Ni is in the +2 oxidation state i.e., in d8 configuration. There are 4 CN− ions. Thus, it can either have a tetrahedral geometry or square planar geometry.
Why is Pt II square planar?
Platinum has bigger d orbitals than nickel does, which can hold more electron density more capably, because the electron density can be more spread out in a larger d orbital. Therefore, platinum can support a higher-energy structure such as the square planar structure.
What is hybridization of PT?
Answer Expert Verified Here valency of Pt is +2. So electrons of 5s becomes zero. The 2 unpaired electron in 4d of Pt get paired and hence there is one vacant orbital. Hence one orbital of 4d, 5s and two orbitals of 5p participates in hybridization, -> resulting in dsp2 type of hybridization and square planar geometry.
What is the hybridization of pdcl4 2?
Thus it is dsp2 hybridisation which is involved in the formation of (PdCl4]2- ion i.e. 4-coordinated complexes of Pd(II) have square planar geometry with n = 0 (diamagnetic). 296.
What is the hybridization of Ni in NiCl4 2?
sp3 hybridization
Answer: There are two unpaired electrons in [NiCl4]2-, a tetrahedral complex with sp3 hybridization in Ni.
Which is a square planar molecule?
Structure of cisplatin, an example of a molecule with the square planar coordination geometry….
| Square planar molecular geometry | |
|---|---|
| Examples | XeF4, PtCl 2− 4 |
| Point group | D4h |
| Coordination number | 4 |
| Bond angle(s) | 90° |
Why is the hybridization of PD(CL4)2- is a square planar?
Why is the hybridization of Pd (Cl4) 2- is a square planar even if it is a high-spin outer orbital complex carrying a weak field ligand whereas Ni (Cl4) 2- is tetrahedral? Firstly, [PdCL4]-2 is a low spin inner orbital complex.
Why is [PdCl4]2- square planar whereas [NiCl4}2- is tetrahedral?
Why is [PdCl4]2- square planar whereas [NiCl4]2- is tetrahedral? The molecule [ P d C l X 4] X 2 − is diamagnetic, which indicates a square planar geometry as all eight d electrons are paired in the lower-energy orbitals. However, [ N i C l X 4] X 2 − is also d 8 but has two unpaired electrons, indicating a tetrahedral geometry.
What is the hybridisation of CN- and Cl-?
CN being strong ligand pairs electron whereas Cl cannot. here you see the hybridisation is sp3 and geometry is tetrahedral. Now , for CN-. The hybridisation is dsp2, and geometry is square planar. For the concept for strong and weak ligand.
What are the hybridization orbitals of PtCl4^-2?
However, since PtCl4^-2 is a planar molecule, in order to describe it, people intuitively mix one S, 2 P and one D orbitals which are sharing a common plane to form dsp2 hybridization orbitals.