What mass of water is produced by the reaction of octane?

To calculate the amount of water produced, we will multiply the obtained number of moles with the molar mass of water. Thus, the mass of water produced in the given reaction is 2.52g.

How do you find the mass of water produced?

As 1 mole of water (H20) have (1×2 + 16) gm = 18 gm mass. Note; mass number of Hydrogen is 1 and oxygen is 16.

What is amount of water produced by the combustion of 8g methane?

According to the above equation, one mole of CH4 (8 g) on combustion gives one mole of carbon dioxide and 2 moles of water and 2 moles of water = 2 x [2 + 8] = 20 g of water.

How many grams of water are produced by the combustion of 32.0 g of CH4?

molecular mass of water is 18. so 36 grams of water will be produced.

How many grams of water are produced by the reaction of 18.0 g of octane?

The mass of 18 moles of water is 324g. Since only 19.8 g of octane is used we use ratio and proportion to determine the amount of water produced. (19.8 / 228.46) * 324 g of water = 28.08 grams of water is produced.

How many moles of water are produced from octane?

If that happens, we know from the balanced equation that for every two moles of octane consumed, we get 18 moles of H2O.

How do you calculate mass produced in a reaction?

Worked Example of Using Mole Ratio to Calculate Mass of Reactant or Product

1. mass O2 = moles(O2) × molar mass(O2) (a) Calculate moles(Mg) = mass(Mg) ÷ molar mass(Mg) moles(Mg) = 12.2 ÷ 24.31 = 0.50 mol.
2. mass MgO = moles(MgO) × molar mass(MgO) (a) Calculate moles Mg. moles(Mg) = mass(Mg) ÷ molar mass(Mg)

How many gram of water is produced by complete combustion of methane?

Answer: 36 gram of water is produced by the complete combustion of methane.

How many moles of water would be produced when 8 g of methane CH 4 are burnt?

1 mol
The number of moles of water produced are. 16gm CH4 produced 2 mol water therefore 8gm will produce 1 mol of water.

How many grams of water will be produced by the complete combustion of 12 g of methane?

Mass of water produced by complete combustion of 12 gram of methane gas is 27 grams.

How many grams of water will be produced by the complete combustion of 16g methane?

According to the above equation, one mole of CH4 (16 g) on combustion gives one mole of carbon dioxide and 2 moles of water and 2 moles of water = 2 x [2 + 16] = 36 g of water.

What is the weight ratio of CO2 produced when burning octane?

The weight of CO 2 is 44 grams per mole (1 x 12 grams/mole for the carbon and 2 x 16 grams/mole for the oxygen atoms). Burning one mole of octane (114 grams), therefore, would produce eight moles of CO 2, with a weight of 352 grams (8 x 44). Thus, the weight ratio of CO 2 produced per octane molecule burned is 352/114, or roughly 3 to 1.

How much does octane weigh in grams?

So, doing the math (8 x 12 + 1 x 18), we see that octane weighs 114 grams/mole. If you combusted all of the octane to carbon dioxide, each of the eight carbon atoms would become part of a CO 2 molecule. Thus, you would have eight CO 2 molecules per octane molecule burned–or eight moles of CO 2 per mole of octane burned.

How many grams of CO2 are in a mole of octane?

The weight of CO 2 is 44 grams per mole (1 x 12 grams/mole for the carbon and 2 x 16 grams/mole for the oxygen atoms). Burning one mole of octane (114 grams), therefore, would produce eight moles of CO 2, with a weight of 352 grams (8 x 44).

What is the molecular weight of C8H18 in grams?

Octane molecular weight Molar mass of C8H18 = 114.22852 g/mol Convert grams Octane to moles or moles Octane to grams