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What is the number of ways in which you can distribute 5 balls in 3 boxes when?

What is the number of ways in which you can distribute 5 balls in 3 boxes when?

As there are 5 balls and three boxes each ball has 3 choices. So to answer is 3x3x3x3x3=243.

How many ways 5 balls can be placed in 3 boxes such that no box remains empty if balls as well as boxes are identical?

So, the number of ways you can put 5 balls in 3 boxes is 21.

How many ways are there to put six Labelled balls into three Labelled boxes where none of the boxes can be empty?

This can be done in P(6,3)=120 ways.

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How many ways can you distribute 4 balls into 5 boxes?

So we take the 40320 ways to areange all 8 elements then divide by the 24 ways to arrange the 4 bars, then divide again by the 24 ways to arrange the 4 dots and we get 70 ways. Much smaller than the 625 (5⁴) ways you can put 4 unique balls into 5 boxes.

How many balls can be in a box?

Each box can contain at most one ball (≤ 1) Each box must contain at least one ball (≥ 1) Each box must contain at least one ball (≥ 1) Each box must contain at least one ball (≥ 1) Each box must contain at least one ball (≥ 1)

How many possible combinations can you make with 12 different balls?

If you choose only one element r = 1 at once from that set, the number of combinations will be 12 – because there are 12 different balls. However, if you choose r = 12 elements, there’ll be only 1 possible combination that includes every ball. Try it by yourself with the n choose r calculator!

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How many K Balls can be distributed into n boxes?

Here, we are counting the number of ways in which k balls can be distributed into n boxes under various conditions. 1. The balls are either distinct or identical. 2. The boxes are either distinct or identical. 3. No box can contain more than one ball or any box may contain more than one ball. 4. No box can be empty or any box can be empty.

How many green balls can you select from a bag?

2 green balls can be selected from 5 green balls and the remaining one ball select from (15 – 5) = 10 balls in 8 C 1 ways. = 80. = 4 / 11. A bag contain 4 red balls, 6 yellow balls and 5 green balls.