What volume of oxygen will react with 200ml of acetylene?

What volume of oxygen at N.T.P is needed to cause the complete combustion of 200 mL of acetylene? Also calculate the volume of carbon dioxide formed. ∴ 200 mL of C2H2 at N.T.P form CO2=2×200 mL = 400 mL.

What volume of oxygen at STP is required to affect complete combustion of 200 cm3 of acetylene and what would be the volume of carbon dioxide formed?

Some Basic Concepts of Chemistry. What volume of oxygen at STP is required to affect complete combustion of 200 cm3 of acetylene and what would be the volume of carbondioxide formed? Thus volume of O2 required = 500 cm3 at S.T.P. According to Gay Lussac’s law of gaseous volumes.

What volume of oxygen is required for complete combustion of acetylene?

So, for complete combustion of 40mL of acetylene, 100 mL of oxygen are required and 80mL of carbon dioxide is formed.

What volume of oxygen would be required to burn completely 400 ml of acetylene C2H2 )? Calculate the volume of CO2 formed?

Explanation: The volume of oxygen required to burn completely 400 ml of acetylene and the volume of carbon dioxide formed. Hence 1000 ml of oxygen is required and 800 ml of carbon dioxide is formed.

What volume of oxygen would be required for the complete combustion of 200 ml of acetylene c2h2 and what would be the volume of co2 produced?

1 mole of acetylene requires 2.5 moles of oxygen for complete combustion. At NTP, 22.4 liters of acetylene requires = 2.5 x 22.4 L of oxygen. So 200 ml of acetylene at NTP requires = 0.2 / 22.4 x 2.5 x 22.4 l of O2 = 0.5 L =500 ml.

What volume of oxygen is required for the complete combustion?

The volume of oxygen required for complete combustion of 0.25 mole of methane at STP is 11.2 dm3. As, we know that, the volume of 1 mole of gas is 22.4 L. Hence, 11.2 dm3 of oxygen required for the complete combustion of 0.25 mole of methane.

What volume of oxygen at STP is needed to cause the complete combustion of 200 mL of c2h2?

What volume of oxygen at STP is needed?

The volume of oxygen gas at STP required for the complete combustion of 200 mL of acetylene gas at STP (1 atm, 273 K) is: 400 mL.

What volume of oxygen at STP is needed to cause the complete combustion of 200 ml of c2h2?

How much oxygen is required for complete combustion?

From the above combustion reaction we can see that 1 mole of carbon requires 1 mole of oxygen (${O_2}$) for its complete combustion. So, for combustion of 83.333 moles of carbon, we will require 83.333 moles of oxygen (${O_2}$). At NTP conditions, 1 mole of a gas occupies 22.4 L of volume.

What volume of oxygen will be required to burn completely 350 ml of acetylene?

Answer: 1 mole of acetylene requires 2.5 moles of oxygen for complete combustion. At NTP, 22.4 liters of acetylene requires = 2.5 x 22.4 L of oxygen. So 350 ml of acetylene at NTP requires = 0.35 / 22.4 x 2.5 x 22.4 l of O2 = 0.875 L = 875 ml.

What volume of oxygen will be required to burn?

At NTP conditions, 1 mole of a gas occupies 22.4 L of volume. So, for combustion of 1 kg of coal, we will require 83.333moles of oxygen (${O_2}$) which occupies $1.866 \times {10^3}$ L of volume at NTP.