What is the greatest 4 digit number divided by 5 10 15 20?
Table of Contents
- 1 What is the greatest 4 digit number divided by 5 10 15 20?
- 2 What is the largest number of 4 digits which when divided by 6 9 12 15 18 leaves 1 as remainder in each case?
- 3 What is the largest 4 digit number that leaves a remainder of 7 when divided by 19?
- 4 What is the greatest 4 digit number exactly divisible by 12 15 20 and 35?
- 5 What is the four digit number which when divided by 12 15 and 21 leaves remainder 7 in each case?
- 6 How do you find the greatest 4 digit number divisible by?
- 7 What is the greatest 4 digit number possible which when divided by 13 leaves the remainder 3 and when it is divided by 5 it leaves the remainder 2?
- 8 What is the largest 4 digit number which when divided by 11 leaves remainder 9?
What is the greatest 4 digit number divided by 5 10 15 20?
Solution(By Examveda Team) ∴ 9960 is the largest four digit number which is completely divided by the given numbers.
What is the largest number of 4 digits which when divided by 6 9 12 15 18 leaves 1 as remainder in each case?
On dividing 1000 by 36, we get remainder as 28. Since number leaves remainder as 3. = 1011. Thus, the least 4-digit number = 1011.
What is the largest 4 digit number that is divisible by each of 14 18 and 24?
9576
∴ The largest 4-digit number that is divisible by each of 14, 18, and 24 is 9576.
What is the largest 4 digit number that leaves a remainder of 7 when divided by 19?
Detailed Solution ∴ 9994 is divisible by 19.
What is the greatest 4 digit number exactly divisible by 12 15 20 and 35?
∴ The largest four-digit number exactly divisible by 12, 15, 20, and 35 is 9660.
What is the largest four digit number which when divided by 11 leaves remainder 9 Find the quotient?
R D Sharma – Mathematics 9 Largest 4 digit number that is divisible by 11 is 9999…
What is the four digit number which when divided by 12 15 and 21 leaves remainder 7 in each case?
To find the largest 4 digit number which, when divided by 12, 15 and 21, leaves remainder 7, we have to divide the 9999 by 420 and add 7 after subtracting the remainder from 9999. When we divide the 9999 by 420, the remainder is 339.
How do you find the greatest 4 digit number divisible by?
If any number N is divisible by a set of numbers a, b, c then the L.C.M. of a, b, and c also divides the number N. Calculation: The greatest 4 digit number is 9999. ∴ The number 9960 is the greatest 4-digit number which is divisible by 2, 3, 4, 5, and 6.
What is the greatest 4 digit number exactly divisible by?
- First we find the LCM of 8,12 and 20.(Refer Fig.1)
- ∴ LCM of given numbers =2×2××3×5=120.
- According to given condition , we need a greatest number of 4 -digit which is exactly divisible by 120.
- Greatest number of 4-digit =9999.
- We divide 9999 by 120 and find the remainder (Refer Fig.2)
- ∴ The required number =9999−39=9960.
What is the greatest 4 digit number possible which when divided by 13 leaves the remainder 3 and when it is divided by 5 it leaves the remainder 2?
Therefore 9831 is the number. Hope this helps!!