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How do you calculate the specific heat capacity of a metal?

How do you calculate the specific heat capacity of a metal?

Use Q = sm∆T to determine the heat capacity of the metal. (Make sure to use the heat given off by the metal, the mass of the metal, and the temperature change of the metal in this calculation.)

How do you find specific heat capacity with only mass and temperature?

The heat capacity and the specific heat are related by C=cm or c=C/m. The mass m, specific heat c, change in temperature ΔT, and heat added (or subtracted) Q are related by the equation: Q=mcΔT. Values of specific heat are dependent on the properties and phase of a given substance.

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What is the formula for calculating heat capacity?

Heat Capacity of an object can be calculated by dividing the amount of heat energy supplied (E) by the corresponding change in temperature (T). Our equation is: Heat Capacity = E / T.

How do you find the specific heat capacity of a substance?

How to calculate specific heat capacity? Find the initial and final temperature as well as the mass of the sample and energy supplied. Subtract the final and initial temperature to get the change in temperature (ΔT). Multiply the change in temperature with the mass of the sample.

What is the specific heat capacity value of copper?

What is the specific heat capacity value of copper? The specific heat of copper is 385 J/kg K. You can use this value to estimate the energy required to heat a 100 g of copper by 5 °C, i.e., Q = m x Cp x ΔT = 0.1 * 385 * 5 = 192.5 J. What is the specific heat capacity value of aluminum?

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What is the formula to calculate the amount of supplied heat?

c = Q / (m * ΔT) Q is the amount of supplied or subtracted heat (in joules), m is the mass of the sample and ΔT is the difference between the initial and final temperature of the sample.

How do you calculate the specific heat of aluminum and water?

Again, you use q = mcΔT, except you assume q aluminum = q water and solve for T, which is the final temperature. You need to look up the specific heat values (c) for aluminum and water. This solution uses 0.901 for aluminum and 4.18 for water: (10) (130 – T) (0.901) = (200.0) (T – 25) (4.18)