How does intensity of radiation vary with wavelength?

The higher the frequency, the shorter the wavelength. This means that the intensity of the radiation emitted is greater for a hotter body. the intensity of the radiation it emits increases. the wavelength that corresponds to the peak intensity gets shorter.

Why is there low intensity of blackbody radiation at very short wavelengths?

Well, we know that the intensity of radiation MUST decrease with short wavelength in black-body radiation because if it didn’t then everything in the universe would immediately cool down to absolute zero through the emission of radiation at arbitrarily short wavelengths.

Is the wavelength of the radiation decreases the intensity of the black-body radiation?

At a given temperature, the intensity of black body radiations first increases up to a specific wavelength than starts decreasing, as the wavelength continues to decrease.

What is the major limitation of Rayleigh-Jeans law?

The Rayleigh–Jeans law agrees with experimental results at large wavelengths (low frequencies) but strongly disagrees at short wavelengths (high frequencies). This inconsistency between observations and the predictions of classical physics is commonly known as the ultraviolet catastrophe.

How does intensity of black body radiation vary as the wavelength?

The blackbody radiation curves have quite a complex shape (described by Planck’s Law). As the temperature of the blackbody increases, the peak wavelength decreases (Wien’s Law). The intensity (or flux) at all wavelengths increases as the temperature of the blackbody increases.

Which one of the following is not correct about black body radiation?

Black surfaces do not emit radiations and hence heat currents from a black surface is not an example of blackbody radiation. Hence option C is not a correct answer.

Which theory explained black body radiation?

Planck’s radiation law, a mathematical relationship formulated in 1900 by German physicist Max Planck to explain the spectral-energy distribution of radiation emitted by a blackbody (a hypothetical body that completely absorbs all radiant energy falling upon it, reaches some equilibrium temperature, and then reemits …

What is Planck’s law of radiation under what condition it reduces to Rayleigh-Jeans law?

At long wavelengths, the Planck distribution reduces to the Rayleigh-Jeans law. This is because the exponential term in the distribution is much smaller than one when the wavelength is large, so it may be approximated by 1 + (hc / λkT). (Recall that ex ≈ 1+ x when x is very small.)

What do you understand by ultraviolet catastrophe how Planck’s law explain ultraviolet catastrophe and Rayleigh-Jeans formula?

The ultraviolet catastrophe, also called the Rayleigh–Jeans catastrophe, was the prediction based on classical physics that an ideal black body at thermal equilibrium will emit more energy as the frequency of radiation increases than it was observed in experiments.