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How many bytes are there in 32 bits address?

How many bytes are there in 32 bits address?

Writing Word-Addressable Memory The previous two code examples have shown a computer architecture with a word-addressable memory. The MIPS memory model, however, is byte-addressable, not word-addressable. Each data byte has a unique address. A 32-bit word consists of four 8-bit bytes.

How many bits are required in the address for memory of 32gb?

432 bytes = 32 Mb. So you will need, at least 25 bits to address a single byte in that memory scheme.

What is a 32-bit memory address?

A 32-bit address is the address of a single byte. Thirty-two wires of the bus contain an address (there are many more bus wires for timing and control). Sometimes people talk about addresses like 0x2000, which looks like a pattern of just 16 bits. But this is just an abbreviation for the full 32-bit address.

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How many bits are needed to address a single word?

Therefore 28 address lines ( bits) will be required to address any single word.

How many bits does it take to address a single byte?

That is, 33.554.432 bytes = 32 Mb. So you will need, at least 25 bits to address a single byte in that memory scheme. 1M is 2^20, 32 is 2^5, so you need 25 bits. Since 1MB = 10^6 bytes i.e. 2^20 bytes for 32 MB we have:

How many bits in 2^15 memory?

As far as I see 2^15 is 32768 which is 32 MB so the answer could be 15 bits. But I think I’m missing something here? 32768 bytes is not 32 Mb. That is, 33.554.432 bytes = 32 Mb. So you will need, at least 25 bits to address a single byte in that memory scheme. 1M is 2^20, 32 is 2^5, so you need 25 bits.

How many different addresses are there in 32 megabytes of memory?

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The length of an address is 16 bits, which means that there are 2^16 = 65,536 different addresses. We know that the main memory is 32 megabytes which is 32 million bytes. Do 65,536 words fit into this memory?

How many bytes are in a single word in memory?

Here’s my homework question which is kind of confusing to me: “A computer has 64 MB of memory, Each word is 4 bytes. How many bits are needed to address each single word in memory?”