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How many volume of CO2 is produced by the combustion of 30 gram of ethane?

How many volume of CO2 is produced by the combustion of 30 gram of ethane?

So 1 mol of Ethane will evolve 2 moles of CO2, ie, 30 gms of ethane will evolve 2*22.4 l of CO2 at STP, so for 150 gms it is 2*5*22.4= 224 l of CO2.

How many liters of CO2 at STP are produced from the complete combustion of 2.00 moles of heptane?

313.6 L
313.6 L of carbon dioxide will be produced from the complete combustion of 2.00 moles of heptane.

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What volume of CO2 gas is formed at STP?

22.4 L
At STP, the molar volume of any ideal gas is 22.4 L. We can identify condition “1” as the volume, temperature, and pressure of the CO2 sample at laboratory conditions and condition “2” as STP.

How do you find the volume of air in combustion?

∴ Total volume of actual products of combustion = (V1 + V) m3. Let O be the percentage of oxygen (by volume) present in the exhaust gases, then the excess quantity of air which will contain this volume of oxygen will be O/21 m3.

How much volume of carbon dioxide is produced when 50 gram of calcium carbonate is heated completely understand condition?

Hence, at STP, ${ 11.2L }$ of carbon dioxide is obtained by thermal decomposition of ${ 50g }$ of calcium carbonate.

How many liters of co2 are produced at STP?

At STP, a mole of gas takes up 22.4 liters. So the dioxide carbon producted will be 0.67/2 moles. Or, it will be 15/2 = 7.5 liters.

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How many Litres of co2 does STP have?

occupies the volume of 22.4 liter. ∴ 1 mole of CO₂ at S.T.P. occupies the volume of 22.4 liter.

What is the volume of gas at NTP?

NTP : NTP – Normal Temperature and Pressure – is defined as air or gas at 20°C (293.15 K, 68°F) and 1 atm (101.325 kN/m2, 101.325 kPa, At these conditions, the volume of 1 mol of a gas is 24.0548 liters.

What is weight and volume of air required for combustion of 2kg of carbon?

Calculate weight of air needed for complete combustion of 2kg of coal containing C=70\%, H=10\%, O=10\%, N=5\% and remaining ash….

Combustion reactions Weight of O2 required(kg)
2) H2+12O2 → H2O 0.1 × 16 1 = 0.8