What is the limiting reactant of CH4?

Methane
Methane is the limiting reagent because the other reactant is the oxygen of air which is always present in excess. Thus the amounts of carbon dioxide & water formed will depend upon the amount of methane burnt.

How many grams of CO2 are produced when one mole of CH4 reacts with excess O2?

To compute for the number of grams of 1.875 moles of CO2, 44 grams per mole is multiplied by 1.875 moles. The product gives 82.5 grams of CO2 produced. The reaction formula CH4 + 2O2 → CO2 + 2H2O shows the oxidation of 1 mole of CH4 (Methane) will yield 1 mole of CO2 (Carbon Dioxide).

What is the limiting reagent in CH4 O2?

Oxygen is our limiting reactant.

What is the mole ratio for CH4 and CO2?

one to one
As we can see from our balanced chemical equation, we need one mole of methane to produce one mole of carbon dioxide, which gives us a molar ratio of one to one.

What is the mole ratio between CH4 and H2O?

Now look at the mole ratio that exists between CH4 and H2O : 1 mole of methane will produce 2 moles of water.

What type of chemical reaction is CH4 2O2 CO2 2H2O?

Incomplete combustion
CH4 + 2O2 → CO2 + 2H2O Incomplete combustion – carbon monoxide and water.

What is the limiting reagent in CO2?

O2 is the limiting reagent and 6 moles of CO2 are produced by the reaction.

How many moles of CO2 are produced from the given amount of CH4?

Since each mole of CH4 consumed produces one mole of CO2, you can say that you will produce 4.5 moles of CO2.

What is the mole ratio of CH4 to CO2?

The molar ratio between CO2 and methane, CH4 is 2:2 or simply 1:1. The mass of carbon dioxide produced from burning 775 g of methane is 2125 g.

What reaction is this CH4 2 O2 → CO2 2 H2O?

CH4 + 2O2 → CO2 + 2H2O Incomplete combustion – carbon monoxide and water.

What is the limiting reactant in CH4 2O2 CO2 2H2O?

To consume the 2.8 moles of CH4 we need 5.6 moles of O2 since the molar ratio is 1:2. We have only 3 moles of O2 ; therefore, O2 is the limiting reactant.