Where is Thevenin voltage across terminals a and B?

Determine the equivalent thevenin’s voltage between terminals ‘a’ and ‘b’ in the circuit shown below. Explanation: The voltage at terminal a is Va=(100×6)/16=37.5V, The voltage at terminal b is Vb=(100×8)/23=34.7V. So the voltage across the terminals ab is Vab=Va-Vb=37.5-34.7=2.7V.

What is the value of Thevenin resistance RTH across AB terminals?

Calculate the Thevenin resistance across the terminal AB for the following circuit. Explanation: Thevenin resistance is found by opening the circuit between the specified terminal and shorting all voltage sources. When the 10V source is shorted, we get: Rth=(1||2)+3=3.67 ohm.

What do you mean by equivalent circuit?

Definition of equivalent circuit : an electric circuit made up of the basic elements resistance, inductance, and capacitance in a simple arrangement such that its performance would duplicate that of a more complicated circuit or network.

How do you verify Thevenin Theorem?

1. RL=VLIL. 3) Remove the load by opening the switch S2 and read the open circuit voltage (or Thevenin equivalent voltage) Vth.
2. Rth=VI. 5) Now compute the load current.
3. IL=VthRth+RL. 6) Compare the above computed load current with its observed value in step (2) and verify the theorem.

How do I find the Norton equivalent circuit?

Example-1 Find the Norton Equivalent Circuit Across Terminals AB.

1. Step-1 Find Norton equivalent current (IN).
2. Step-2 Find equivalent resistance (REQ).
3. Step-3 Put the value of Norton current and equivalent resistance in the Norton equivalent circuit.
4. Step-1 Find the Norton current (IN).

How does Norton calculate current equivalent?

Any collection of batteries and resistances with two terminals is electrically equivalent to an ideal current source i in parallel with a single resistor r. The value of r is the same as that in the Thevenin equivalent and the current i can be found by dividing the open circuit voltage by r.

How do you solve equivalent circuits?

This can be obtained by doing the following simplification.

1. RDE=6×66+6=3612=3Ω
2. RFG=4+8=12Ω
3. RCE=3+3=6Ω
4. RCB=6×126+12=7218=4Ω
5. RAB=2+4=6Ω