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Can complete a work in 10 days B can complete a work it in 15 days in how many days will the work be completed if they work together?

Can complete a work in 10 days B can complete a work it in 15 days in how many days will the work be completed if they work together?

In two days, A and B will complete 10 units of work. Remaining 20 units can be completed by A in 10 days (at rate of 2 units per day). Hence, whole work will be completed in 12 days. The correct option is C.

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Does 7/10 part of work in 15 days after that he completes the remaining work in 4 days with the help of B in how many days will A and B together do the same work?

A does 7/10 part of work in 15 days. After that he completes the remaining work in 4 days with the help of B….Correct Option: C.

∵ (A + B) take 4 days to do 3 work
10

Can finish a work in 18 days and B can do the same work in 15 days b worked for 10 days and left the job in how many days a alone can finish the remaining work 05?

A can finish a piece of work in 18 days and B can do the sam work in 15 days,B worked for 10 days and left the job.In how many days, A alone can finish the remaining work? B’s 10 days work = 6×10=60 units .

Can complete a work in 10 days?

A, B and C together one day work = (1/4). So one day work of A + one day work of B + one day work of C = A, B and C together one day work. ⇒x=10 Days. Therefore C can finish the work alone in 10 days.

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Does a work in 10 days and B does the same work in 15 days in how many days they together will do the same work *?

∴ They together will do the same work in 6 days.

Can do a work in 10 days?

So one day work of A + one day work of B + one day work of C = A, B and C together one day work. ⇒x=10 Days. Therefore C can finish the work alone in 10 days. So this is the required answer.

How many days a alone can finish the remaining work?

In how many days, A alone can finish the remaining work? work is done by A in 1 day. = 6 days.

Can do a piece of work in 10 days B in 12 days and C in 15 days?

1 Answer

  • A’s one day’s work = 1/10.
  • B’s one day’s work = 1/12.
  • C’s one day’s work = 1/15.
  • A, B and C’s one day’s work = 1/10 + 1/12 + 1/15.
  • = (6 + 5 + 4)/60 = 15/60 = ¼
  • Let the work completed in x days.
  • ∴ A’s 2 days work + B’s (x – 3) days work + C’s x days work = 1.
  • ⇒ 2 × (1/10) + (x – 3) × 1/12 + x × (1/15) = 1.