How many NAND gates are required for making XOR gate?

four NAND gates
An XOR gate circuit can be made from four NAND gates. In fact, both NAND and NOR gates are so-called “universal gates” and any logical function can be constructed from either NAND logic or NOR logic alone.

How do you make a NAND gate from XOR?

An XOR gate is made by connecting four NAND gates as shown below. This construction entails a propagation delay three times that of a single NAND gate. , noting from de Morgan’s Law that a NAND gate is an inverted-input OR gate. This construction uses five gates instead of four.

What is the minimum number of 2 input NAND gates required to implement the XOR?

He said, An XOR gate circuit can be made from four NAND or five NOR gates in the configurations shown below. In fact, both NAND and NOR gates are so-called “universal gates,” and any logical function can be constructed from either. Donn (2010) developed an XOR gate using a four (4) two input NAND gates.

Can we use NAND gate to make any other gates?

NAND gates can also be used to produce any other type of logic gate function, and in practice the NAND gate forms the basis of most practical logic circuits. By connecting them together in various combinations the three basic gate types of AND, OR and NOT function can be formed using only NAND gates, for example.

How are NAND gates formed?

A NAND gate is made using transistors and junction diodes. By De Morgan’s laws, a two-input NAND gate’s logic may be expressed as AB=A+B, making a NAND gate equivalent to inverters followed by an OR gate. The NAND gate is significant because any boolean function can be implemented by using a combination of NAND gates.

How do you make NAND?

A two-input NAND gate produces a LOW output if both of its inputs are HIGH, and a HIGH output otherwise. It’s easy enough to create a NAND gate by using just two transistors.

How many two input NAND gates are required to implement 3 input NAND gate?

With 3 NAND gates. Another under it but common the inputs together and call them C (Ok that’s a NOT gate as correctly pointed out in the comment). Using 2 NAND gates…. The output from that second NAND should equal 3 input NAND.

How do you prove a NAND gate is a universal gate?

An OR gate can be replaced by NAND gates as shown in the figure (The OR gate is replaced by a NAND gate with all its inputs complemented by NAND gate inverters). Thus, the NAND gate is a universal gate since it can implement the AND, OR and NOT functions.