How many ways can a consonant and a vowel be chosen out of the letters of the word logarithm?

Answer: Total ways can a consonant and a vowel be chosen out of the letters of the word logarithm is 18.

How many ways are there to select a vowel and a consonant from extinction?

Discussion :: Permutation and Combination – General Questions (Q. No. 4)

How can a consonant and a vowel be chosen from the letters of the word courage?

Now in the given word ‘COURAGE’ there are 3 consonants that are (c, r, g) and there are 4 vowels that are (o, u, a, e). So out of 3 consonants a single consonant can be chosen in $^3{C_1}$ways. (A, E, I, O, U) are the vowels while rest are marked as consonants.

How many arrangements of the letters of the word logarithm begin with a vowel and end with a consonant?

how many of the arrangement of the letter of the world “LOGARITHM” begin witha vowel and end with a consonant. .. .. ……….. Answer = 90720.

How many words can be formed from the letters of the word dogmatic?

(b)find n if (n+2)! =2550⋅n! There are 3 condidates for a Classical; 5 for a Mathematical and 4 for a Natural science scholarship. (i)In how many ways can these scholarship be awarded? (ii) In how many ways one of these scholarships be awarded?

How many different words containing all the letters of the word triangle can be formed?

The total number of words that can be formed using all the 8 letters of the word ‘ TRIANGLE ‘ is P(8, 8) = 8 ! = 40320. We have given the word TRIANGLE. Now, TRIANGLE word consist of 8 alphabets, including 3 vowels (A, E, I ) and 5 consonants ( T, R, N, G, L ).

How many words can be formed from the letter of the word registered if all vowels are together?

Hence, a total number of words formed during the arrangement of letters of word UNIVERSITY such that all vowels remain together is equals to 60480.

How many words can be formed by using all letters of word given?

Total number of words =11(3!) ×(3!) ×(2!) =554400.