Common

What are the units in the ring of Gaussian integers Z i?

What are the units in the ring of Gaussian integers Z i?

Let (Z[i],+,×) be the ring of Gaussian integers. The set of units of (Z[i],+,×) is {1,i,−1,−i}.

What are all units in the ring of Gaussian integers?

The units of the ring of Gaussian integers (that is the Gaussian integers whose multiplicative inverse is also a Gaussian integer) are precisely the Gaussian integers with norm 1, that is, 1, –1, i and –i.

How do you prove a Gaussian integer is irreducible?

A Gaussian integer is called irreducible if its only divisors are units and its associates. Notice that if N(z) is a prime, then z is irreducible since if z = w1w2, it follows that N(z) = N(w1)N(w2), from which it follows that either w1 or w2 is a unit.

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Is the ring of Gaussian integers a field?

The Gaussian integer Z[i] is an Euclidean domain that is not a field, since there is no inverse of 2.

How do you factor Gaussian integers?

Note that there are rational primes which are not Gaussian primes. A simple example is the rational prime 5, which is factored as 5=(2+i)(2−i) in the table, and therefore not a Gaussian prime….Factorizations.

norm integer factors
89 5+8i 8+5i (p) (p)
90 3+9i 9+3i (1+i)·(2+i)·3 (1+i)·(2−i)·3
97 4+9i 9+4i (p) (p)
98 7+7i (1+i)·7

Is 7 4i an irreducible Gaussian integer?

Note that there are rational primes which are not Gaussian primes….Factorizations.

norm integer factors
65 1+8i 4+7i 7+4i 8+i i·(2+i)·(3−2i) (2+i)·(3+2i) i·(2−i)·(3−2i) (2−i)·(3+2i)
68 2+8i 8+2i (1+i)2·(4−i) −i·(1+i)2·(4+i)
72 6+6i −i·(1+i)3·3
73 3+8i 8+3i (p) (p)

Is Zi irreducible 3?

Let Z[i] be the ring of Gaussian integers. Then 3 is prime in Z[i] but 5 is not. Moreover, if a prime p is not prime in Z[i], then either p = 2 or p ≡ 1 mod4.

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How do you find Gaussian factors?

This is defined as: N( a + b i) = a 2 + b 2. In the next to last expression we used the fact that i2 = -1. This means that the first step when trying to factor a Gaussian integer is to factor its norm into integer primes, so we get the norm of the factors of the original number.