What is the linear velocity of the Earth at the equator?
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What is the linear velocity of the Earth at the equator?
At the equator, linear speed with respect to the polar (day/night spin ) axis is 463.82 meter/s = 1521.8 feet/s, At latitude 15oNand15oS , this speed is 447.77 meter/s = 1469.1 feet/s.
How do you find angular velocity with radius?
We can rewrite this expression to obtain the equation of angular velocity: ω = r × v / |r|² , where all of these variables are vectors, and |r| denotes the absolute value of the radius. Actually, the angular velocity is a pseudovector, the direction of which is perpendicular to the plane of the rotational movement.
What is the angular velocity of a point at the equator of the Earth?
Angular Speed of the Earth
| Bibliographic Entry | Result (w/surrounding text) | Standardized Result |
|---|---|---|
| World Book Encyclopedia Vol 5. Illinois: Field Enterprises Educational Corporation:1961: 13. | “17.5 miles a minute at the equator is the speed of the earth. 0.0044 rad/min” | 7.367 × 10−5 rad/s |
How do you find linear speed at the equator?
The linear speed on a point at the equator on the surface of the Earth is going to be the radius of the Earth multiplied by this angular speed. So that’s 6.4 times 10 to the 6 meters—radius— times 2π radians over 86400 seconds which is 470 meters per second.
How do you find the angular velocity of the earth?
When calculating the angular velocity of the Earth as it completes a full rotation on its own axis (a solar day), this equation is represented as: ωavg = 2πrad/1day (86400 seconds), which works out to a moderate angular velocity of 7.2921159 × 10-5 radians/second.
How did they find the radius of Earth?
This means that Eratosthenes estimated the circumference of the Earth to be about 40,000 km. He also knew that the circumference of a circle was equal to 2 times π (3.1415…) times the radius of the circle. (C = 2πr) With this information, Eratosthenes inferred that the Earth’s radius was 6366 km.