What is the minimum number of comparisons?

for 4 elements the min. number of comparisons is 3. In general, to find largest of N elements you need N-1 comparisons. This gives you 4 for 5 numbers, not 6.

What is the maximum number of comparisons needed to sort a decimal number of 3 digit?

Answer: 360 maximum number of comparisons.

What is the least number of comparisons needed to sort four elements?

So that’s five. For smaller number of inputs you can generate optimal sorting networks that provides that minimum number of comparisons necessary.

What is the least number of comparisons which are required to find the minimum and the maximum of 100 numbers?

3 comparisons
The minimum number of comparisons required to find the minimum and the maximum of 100 numbers is ______________. Therefore, we need 3 comparisons for each 2 elements, so total number of required comparisons will be (3n)/2 – 2, because we do not need to update min or max in the very first step.

What is the smallest number of comparisons needed to find the minimum and maximum?

The formula for the minimum number of comparisons to find the minimum and the maximum elements is ( 3n / 2 ) – 2 where n is the size of the array.

How many comparisons are needed to sort 5 elements if a straight selection sort is used and array is already in the opposite order?

+ 2 + 1 = n(n − 1) / 2 ∈ Θ(n^2) comparisons. So, for 5 elements, it’d be 5*4/2 = 20/2 = 10 (note “none of the loops depend on the data in the array”, so the fact that it’s in descending order doesn’t play a role in the number of comparisons).

How many numbers of comparisons are required in insertion sort to sort a file if the file is already sorted?

Part (b) of Figure 5.15 shows that only four comparisons are required by the algorithm when the input list is already presorted. This is different from the selection sort algorithm which always requires a fixed number of comparisons to sort N items, regardless of their original order.

How many comparisons does radix sort have?

Total number of comparisons= 10*4=40 (10 because I iterated through all buckets to look for corresponding bucket). Now the problem is in the book by Timothy J Williams its given no of comparisons= no of digits* no of numbers * no of buckets= 4*7*10=280.

How many no of passes are required in radix sort If the largest number in a array contains n digits?

Radix sort algorithm requires the number of passes which are equal to the number of digits present in the largest number among the list of numbers. For example, if the largest number is a 3 digit number then that list is sorted with 3 passes. The Radix sort algorithm is performed using the following steps…

Which sort uses the least comparisons?

Assuming that your music library has no order to it, merge sort is the best sorting algorithm to use.

Which sort has least comparison?

Merge-insertion sort is the sorting algorithm with the minimum possible comparisons for n items whenever n ≤ 15 or 20 ≤ n ≤ 22, and it has the fewest comparisons known for n ≤ 46.