What is the reference circle of simple harmonic motion?
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What is the reference circle of simple harmonic motion?
Simple Harmonic Motion and the Reference Circle. The ball is moving in uniform circular motion (see Section 5.1) on a path known as the reference circle. Figure 10.8 The ball mounted on the turntable moves in uniform circular motion, and its shadow, projected on a moving strip of film, executes simple harmonic motion.
We can conclude that, if a particle moves in a uniform circular motion, its projection can be said to move in a simple harmonic motion, where the axis of oscillation is the diameter of the circle or in other words, simple harmonic motion is the projection of uniform circular motion along the diameter of the circle on …
How can we obtain the equation of SHM?
The differential equation of linear S.H.M. is d2x/dt2 + (k/m)x = 0 where d2x/dt2 is the acceleration of the particle, x is the displacement of the particle, m is the mass of the particle and k is the force constant. We know that k/m = ω2 where ω is the angular frequency.
What is reference particle and reference circle?
SHM can be obtained by perpendicular projection of uniform circular motion of a particle on its diameter such a particle is called reference particle and its circular path is called reference circle.
Is SHM a uniform motion?
Therefore, simple harmonic motion is defined as the projection of uniform circular motion on any diameter of a circle of reference.
Is SHM a circular motion?
What is the difference between SHM and circular motion?
The one-dimensional projection of this motion can be described as simple harmonic motion. A point P moving on a circular path with a constant angular velocity ω is undergoing uniform circular motion. This can be compared with the projection of the linear vertical motion of an oscillating mass on a spring.
What is SHM equation?
simple harmonic motion, in physics, repetitive movement back and forth through an equilibrium, or central, position, so that the maximum displacement on one side of this position is equal to the maximum displacement on the other side. That is, F = −kx, where F is the force, x is the displacement, and k is a constant.
Why acceleration is zero at mean position in SHM?
At mean position, the displacement of the particle is zero. Here, k is the force constant and x is the displacement from the mean position. Therefore, the acceleration of the particle at mean position is zero.