How many ways can you split 10 players into two teams of 5 players each?

Solution. There are (105)=10×9×8×7×65×4×3×2×1=252 ways of chosing the starting five. The number of ways of dividing the squad into two teams of five is 2522=126.

How many ways can you split 12 people?

5775 different ways
Answer: You can split 12 people into 3 teams of 4 in 5775 different ways.

How many ways are there to place 12 people into 4 groups of equal size?

In how many ways can we divide 12 students in groups of fours. A group of 4 can be chosen from 12 students is : 4C12=495 which is wrong answer and answer is 5775 Please help on this..

How many ways are there to divide twelve students into two groups of six each?

= 77*6 = 462 ways.

How many ways can you divide into two groups?

Suppose x is a particular element of the set. The two groups are completely determined by choosing which of the remaining N−1 elements are in the same subset as x. There are 2N−1 ways to choose a subset of the remaining N−1 elements, so there are 2N−1 ways of dividing the set into two groups.

How many pairs of 10 people are there?

2m×m!. This gives the following sequence of values: 1,3,15,105,945,10395,135135,2027025,34459425,654729075,… In particular we get for ten people that there are 945 arrangements (fifth term in the sequence with m=5 and five pairs for 10 people in total).

How many different ways can 10 people be arranged?

3,628,800 ways to line up 10 people.

How many ways can you divide 8 people into 4 teams?

In the process described above, every possible way of dividing 8 people into 4 teams of 2 people each has been counted 4! = 24 times. So the number of ways of dividing a group of 8 people into 4 teams of 2 people each = 28 * 15 * 6 / 24

How many ways are there of choosing the second team?

The first of your 3 teams has 4 people in it. So you are choosing 4 people from 12. In teams the order you pick people doesn’t matter, so there are ( 12 4) = 495 ways of choosing the first team. This leaves 8 people left for the second team. there are ( 8 4) = 70 ways of choosing the second team.

How many ways can you choose two people from a group?

There are C (4, 2) = 6 ways that you can chose the people in the first of the two groups. If the question had just asked, “How many ways can you chose two people to form a group from a group of four?” we would be done here. In this kind of classic combinatorics question, we aren’t concerned with what’s going on with the people who weren’t chosen.

How many of the remaining 8 people are in the first team?

The first team: 12 choose 4 = ( 12 4). Then the second team would be 4 of the remaining 8 people: ( 8 4). The last team would be 4 of the remaining 4, which obviously equals 1, but to be thorough: ( 4 4).