How much volume of CO2 is produced when 50g of CaCO3 is heated?
Table of Contents
- 1 How much volume of CO2 is produced when 50g of CaCO3 is heated?
- 2 How much volume is occupied by the CO2 when the 100 grams of CaCO3 is decomposed?
- 3 What volume does CO2 release at STP?
- 4 What is the volume of carbon dioxide at STP?
- 5 What volume does CO2 evolve at STP?
- 6 What is the volume of CO2 produced at STP?
How much volume of CO2 is produced when 50g of CaCO3 is heated?
22 g of CO2 are obtained from decomposition of 50 g of CaCO3.
How much volume is occupied by the CO2 when the 100 grams of CaCO3 is decomposed?
So 100- g of 100\% pure CaCO3 on complete dissociation will produce 44- g of CO2- gas.
What volume of CO2 at STP will be produced by 1 mole of CaCO3?
When one mole of calcium carbonate (CaCO3) reacts with one mole of hydrochloric acid (HCl), it produces one mole of carbon dioxide (CO2), at S.T.P one mole of carbon dioxide’s density is 0.00195g/cm3 and weight of one mole of carbon dioxide is around 44gms so the volume of carbon dioxide corresponds to 22,400cm3.
What volume of CO2 is formed at STP when 10 g of CaCO3 undergoes calcination?
10 g calcium carbonate corresponds to 0.1 mol. It on decomposition will give 0.1 mol of carbon dioxide. But limestone is only 90\% pure. Hence, 0.09 mol of carbon dioxide will be obtained.
What volume does CO2 release at STP?
The volume of carbon dioxide obtained at STP is $1.12\,litre$. So, the correct answer is Option B . Note: We must remember that the equal volume of all gases at the standard temperature and pressure comprises the same number of particles.
What is the volume of carbon dioxide at STP?
22.4 L
At STP, the molar volume of any ideal gas is 22.4 L. We can identify condition “1” as the volume, temperature, and pressure of the CO2 sample at laboratory conditions and condition “2” as STP.
What volume of carbon dioxide is produced at STP?
The volume of 1 mole of CO2 at STP is equal to 22.4 Liters. The question did not specify the number of mole or any other given. You can use the Ideal Gas Law (PV=nRT) to find that a mol of Ideal Gas occupies 22.4 L at STP.
What volume of CO2 is obtained at STP?
At STP: 1 mole of a gas occupies 22.4 L of volume. So, 0.093 moles of carbon dioxide will occupy = 0.093X22. 4=2.08 L of carbon dioxide.
What volume does CO2 evolve at STP?
On heating this, one mole of CO2 is evolved which takes up 22.4L at STP.