What chords are equidistant from the center of the circle?

Chords that have an equal length are called congruent chords. An interesting property of such chords is that regardless of their position in the circle, they are all an equal distance from the circle’s center. The distance is defined as the length of a perpendicular line from a point to a line.

When the two chords of a circle are parallel are the arcs they intercept be congruent How about the arcs they cut off?

Chords. Chords within a circle can be related many ways. Parallel chords in the same circle always cut congruent arcs. That is, the arcs whose endpoints include one endpoint from each chord have equal measures.

What is equidistant from the centre of a circle are equal in length?

chords
Since corresponding parts of congruent triangles are equal. Also, we know that the perpendicular from the center of a circle to a chord divides the chord into two equal halves. Hence proved. Therefore, chords equidistant from the center of a circle are equal in length.

When two chords intersect in the interior of a circle each chord is divided into two segments that are called?

Using Segments of Chords, Tangents, and Secants When two chords intersect in the interior of a circle, each chord is divided into two segments that are called segments of the chord.

What are parallel chords?

A sequence of chords consisting of intervals that do not change as the chord moves.

How do you prove that chords equidistant from the Centre are equal in length?

Since corresponding parts of congruent triangles are equal. Also, we know that the perpendicular from the center of a circle to a chord divides the chord into two equal halves. Hence proved. Therefore, chords equidistant from the center of a circle are equal in length.

How do you prove that chords are equidistant from the Centre are equal?

Theorem: Equal chords of a circle are equidistant from its center. Proof: Compare ΔOAX Δ O A X with ΔOCY Δ O C Y . By the RHS criterion, ΔOAX≡ΔOCY Δ O A X ≡ Δ O C Y . Thus, OX = OY, which means that AB and CD are equidistant from O.