What is a 1/2 heat exchanger?

Most shell-and-tube heat exchangers are either 1, 2, or 4 pass designs on the tube side. This refers to the number of times the fluid in the tubes passes through the fluid in the shell. In a single pass heat exchanger, the fluid goes in one end of each tube and out the other.

Can the effectiveness of a heat exchanger be greater than one?

The heat transfer effectiveness is always less than the actual heat transfer. …

Which type of heat exchanger has higher LMTD?

The LMTD is a logarithmic average of the temperature difference between the hot and cold feeds at each end of the double pipe exchanger. For a given heat exchanger with constant area and heat transfer coefficient, the larger the LMTD, the more heat is transferred.

How do you calculate lmtd?

Formula for LMTD calculation – For a Parallel Flow Heat Exchanger, Hot fluid entering at temperature 100 degree Celsius and exiting at 90 degree Celsius . Cold fluid Entering at 30 degree Celsius and exiting at 50 degree Celsius. Find the LMTD . LMTD = ((100 – 30)-(90-50)) / ln (100-30/90-50) = 53.6 degree Celsius .

What is clearance in heat exchanger?

Clearance is the distance between tubes. It should be larger than 25\% of the tube diameter. Triangular or square arrangement of tubes are quite common.

What is the difference between LMTD and NTU method?

The LMTD method is convenient for determining the overall heat transfer coefficient based on the measured inlet and outlet fluid temperatures. The ε-NTU method is more convenient for prediction of the outlet fluid temperatures if the heat transfer coefficient and the inlet temperatures are known.

How do you calculate LMTD in heat exchanger?

How do you determine LMTD for counter current flow heat exchanger?

by definition given above, LMTD for counter current flow = (60-50) / ln(60/50) = 10 / 0.1823 = 54.850C. For co-current heat exchanger, ΔT1 = TH1 – TC1 = 100 – 30 = 700C (At first end hot and cold fluids enter the heat exchanger.) (At the other end hot and cold fluids exit the heat exchanger.)

How does the LMTD for a heat exchanger differ from the arithmetic mean temperature difference?

In arithmetic mean temperature difference you have to find temperature difference on whole lengh of heat exchanger. Then, find add them and divide by total number of readings and you will get your answer. In Logarithmic mean temperature difference you have to find temperature on inlet and outlet point.

What should be the minimum value of the correction factor to get multiplied to lmtd?

2. What should be the minimum value of the Correction Factor to get multiplied to LMTD? Explanation: The value of corrected LMTD should be less than the theoretical LMTD considering countercurrent flow. Thus the LMTD correction factor is less than 1.