When one mole of an ideal gas is compressed to half of its initial volume?

When one mole of an ideal gas is compressed to half of its initial volume and simultaneously heated to twice its initial temperature, the change in entropy of gas (DelataS) is: Cp,mln2.

What is the volume of an ideal gas which is compressed from?

So, the volume of an ideal gas is 22.41 L/mol at STP.

Which of the following processes is used to do maximum work done on ideal gas that is compressed to half of its initial volume?

adiabetic process
Maximum area covered under ic – Hence maximum work done during adiabetic process.

Which of the following deviates maximum from ideal Behaviour?

Real gases show deviation from ideal behaviour at high temperature and low pressure.

When an ideal gas is compressed adiabatically and reversibly The final temperature is?

the same as initial temperature.

Which process results in maximum work done?

adiabatic process
The work done in adiabatic process is maximum. This is because the rate of pressure increase is faster in the adiabatic process as all the energy of the work done on the system increases its internal energy.

During Which of the following processes the work done by the gas is the maximum?

Answer is (B) Isobaric. The work done in a thermodynamic process is equal to the area under the P-V diagram.

Can ideal gas be liquefied?

An ideal gas cannot be liquefied because there is no intermolecular force of attraction between the ideal gas molecules. Non-ideal gases show high intermolecular interaction, so liquification of these gases are controlled by two factors – lowering in temperature and increase in pressure.

Which gas will show maximum deviation from ideal gas Behaviour?

* NH$_3$(g) is a polar molecule as it has a presence of hydrogen bonding. * In NH$_3$(g), there are strong intermolecular forces of attraction, so the van der waals constant value is high. Therefore, the maximum deviation from ideal gas is expected from NH$_3$(g). Thus, the correct option is D.