What is the work done in an isothermal expansion?
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What is the work done in an isothermal expansion?
When an ideal gas is subjected to isothermal expansion (∆T = 0) in vacuum the work done w = 0 as pex=0. As determined by Joule experimentally q =0, thus ∆U = 0.
How do you calculate work done in isothermal compression?
Substituting for p, we obtain dW = (nRT/V) dV. Since the temperature, T, is constant (isothermal process), we can integrate the work from the initial to the final volume. Note that the work done by the gas is the negative of the work done on the gas: Wby = − Won. Positive work is done on the gas.
Why is internal energy zero for isothermal process?
For ideal gases, the change in internal energy is zero for an isothermal process since an ideal gas has no interactions between particles, no intermolecular forces, so pressure change at constant temperature does not change internal energy.
What is the work done in isothermal process Class 11?
In isothermal expansion the work is done by the gas whereas in isothermal contraction the work is done on the gas. This implies W>0, work is positive which means work is done by the gas that is heat is absorbed by the gas. This implies W<0, work is negative which means work is done on the gas that is heat is released.
In which case is the work done more and why a isothermal compression B adiabatic compression?
Area under p-v curve gives work done. Since slope of adiabatic process is y(gamma) times isothermal process whose slope is (-p/v). Therefore area under adiabatic process is more compared with isothermal. Hence work done in adiabatic compression is more then isothermal compression.
How is the internal energy change in isothermal process?
In case of isothermal process, there is no change in temperature so the change in internal energy is also zero. So internal energy of the system remains constant.
What is Delta W in isothermal process?
For an ideal gas, in an isothermal process, ΔU=0=Q−W, so Q=W. In Isothermal process the temperature is constant. The internal energy is a state function dependent on temperature. Hence, the internal energy change is zero.
How are Q and W related during this isothermal expansion?
The total work done by the system must equal the amount of heat exchanged during the entire process of expansion and compression. W provides energy output, while Q provides energy input. They are equal in magni- tude. Q provides energy output, while W equals to zero.