What would be the final temperature of a mixture of 50g of water at 20 C and 50g of water at 40 C?

Answer : Let the final temperature of the mixture of 50g of water at 20°C temperature and 50g of water at 40°C be T. Let the specific heat capacity of water be S. Hence, the final temperature of a mixture of 50g of water at 20°C temperature and 50g of water at 40°C temperature would be 30°C.

When one liter of water at 30 Celsius is mixed with 1 Litre of water at 50 degrees Celsius What is the temperature of the mixture?

Answer : One litre of water at 30°C is mixed with one litre of water at 50°C. The temperature of the mixture will be between 30°C and 50°C.

What is the temperature of water in a styrofoam cup?

Problem #13: A metal sample weighing 30.66 g is at a temperature of 81.0 °C when it is placed in a styrofoam cup containing 40.0 g of water at 23.0 °C. The temperature of water rose to 25.0 °C.

How do you calculate specific heat capacity of water?

Calculate specific heat as c = Q / (mΔT). In our example, it will be equal to c = -63,000 J / (5 kg * -3 K) = 4,200 J/(kg·K). This is the typical heat capacity of water. If you have problems with the units, feel free to use our temperature conversion or weight conversion calculators.

How do you calculate the amount of heat lost to cooler water?

Keeping in mind that the heat lost by the warmer must equal the heat gained by the colder, we have this: heat lost to cooler water by condensing steam + heat used to warm cooler water = heat gained by the cooler water Please note again that there are TWO sources of heat energy (steam condensing, then the warm water cooling down).

What is the specific heat of fusion of water?

Problem #5:364 g of water at 34.0 °C is added to ice at 0.0 °C. If the final temperature of the system (which you can assume is isolated) is 0.0 °C, determine how much ice melted. The specific heat of water is 4186 J/kg ⋅ °C. The latent heat of fusion for water is 335,000 J/kg. Solution: 1) Determine energy lost by warm water: