What is the smallest number which when divided by 20 25 35 40 leaves a remainder of 14 19 29 34?
Table of Contents
- 1 What is the smallest number which when divided by 20 25 35 40 leaves a remainder of 14 19 29 34?
- 2 What is the smallest number which is divisible by 15 and 20 without a remainder?
- 3 What is the smallest number which when divided separately by 15 20 and 48 will in each case leaves 9 as remainder?
- 4 How do you find the smallest 4 digit number which is divisible by 18 24 and 32?
- 5 Which is the smallest number that leaves a remainder of 5 when divided by 15 and 18?
- 6 What is the greatest number which when divides 15/18 24 and 36 leaves remainder 3 in each case?
What is the smallest number which when divided by 20 25 35 40 leaves a remainder of 14 19 29 34?
1394
The smallest number which when divided by 20, 25, 35 and 40 leaves a remainder of 14, 19, 29 and 34 respectively, is 1394.
What is the smallest number which when divided by 25 40 and 60?
Hence, 609 is the least number which when divided by 25, 40 and 60 leaves 9 as remainder in each case.
What is the smallest number which is divisible by 15 and 20 without a remainder?
5 is the smallest number which is divisible by 15 and 20.
What is the least smallest number which when divided by 15 20 or 25 will leave a remainder 5 in each case?
425 is the correct answer as L.C.M. of 15,20 ad 35 is 420. So required no. =420+5=425. Then it leaves remainder 5 in each case.
What is the smallest number which when divided separately by 15 20 and 48 will in each case leaves 9 as remainder?
The answer is 249. 249 divided by 15 or 20 or 48 leaves a remainder of 9 in each case.
What is the smallest number which when divided by 25 40 and 60 leaves the remainder 7 in each case?
lcm of 25,40,60:600. So the number is 600+7=607. therefore 607 is the smallest no.
How do you find the smallest 4 digit number which is divisible by 18 24 and 32?
Therefore, we need to subtract 136 and add 288 to make the smallest 4 digit number exactly divisible by18, 24, and 32. So, the multiple of 288 just above 1000 is: 1000 – 136 + 288 = 1152. Hence, the smallest 4-digit number which is divisible by 18, 24, and 32 is 1152.
What is the least number which when divided by 15 leaves?
Complete step-by-step answer: Hence, the least number which satisfies the given condition is equal to 515.
Which is the smallest number that leaves a remainder of 5 when divided by 15 and 18?
Therefore, the required number = 90+5 = 95 As a result, 95 is the smallest number, with a remainder of 5 in each case when divided by 6, 15, and 18.
What is the least number which when divided by 36 and 48 leaves 8 as remainder in each case?
Answer: if we divide 440 by 48 and 36 leaves 8 as remainder.
What is the greatest number which when divides 15/18 24 and 36 leaves remainder 3 in each case?
∴ The required number is 1089.
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