Questions

Which part of a circle is perpendicular bisector of one of its chords?

Which part of a circle is perpendicular bisector of one of its chords?

center
The center of the circle is equidistant from the two endpoints of the chord because they lie on the circle. Therefore, the center lies on the perpendicular bisector of the chord. That is, the perpendicular bisector contains the center.

What does the perpendicular bisector of a chord pass through?

Theorem: The perpendicular bisector of any chord of a circle will pass through the center of the circle. This theorem leads us to a simple corollary, which is discussed next.

What is the relationship between chord of a circle and a perpendicular to it form the centre?

The perpendicular from the center of the circle bisects the chord.

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What is the perpendicular bisector in a circle?

The perpendicular line from the center of a circle O bisects the chord SR. Conversely, the line segment through O bisecting SR is perpendicular to SR. Drag the brown point A to change the figure.

Whats a perpendicular bisector in a circle?

A perpendicular bisector of a line segment is a line segment perpendicular to and passing through the midpoint of (left figure). The perpendicular bisector of a line segment can be constructed using a compass by drawing circles centered at and with radius and connecting their two intersections.

What is a perpendicular bisector of a circle?

Why does the perpendicular bisector of a chord pass through the center of the circle?

The perpendicular bisector of any chord of any given circle must pass through the center of that circle. From this it is manifest that, if in a circle a straight line cut a straight line into two equal parts and at right angles, the centre of the circle is on the cutting straight line.

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How do you find the perpendicular bisector of a line?

A straightforward way of finding a perpendicular bisector is to measure a line segment that you need to bisect. Then divide the measured length by two in order to find its midpoint. Draw a line out from this midpoint at a 90 degrees angle.