How do you find the area of a triangle whose vertices are given?

The formula for the area of the triangle is given by S=12[x1(y2−y3)+x2(y3−y1)+x3(y1−y2)] , where, (x1,y1),(x2,y2),(x3,y3) are the coordinates of the three vertices of the triangle. The units of the area are assumed to be square units.

How do you find the area of a rectangle with coordinates?

The area of rectangle can be found by multiplying the width and length of the rectangle. To find the length of the rectangle compare the x values of two of the coordinates: Since the length is . To find the width of the rectangle we need to look at the y coordinates of two of the points.

How do you find the area of a triangle PQR?

From the figure, the area of a triangle PQR, lines such as ←→ QA Q A ↔, ←→ P B P B ↔ and ←→ RC R C ↔ are drawn from Q, P and R, respectively perpendicular to x – axis. Now, three different trapeziums are formed such as PQAB, PBCR and QACR in the coordinate plane. Now, calculate the area of all the trapeziums.

How to find the length of a triangle using coordinates?

The length can be found using the distance formula. The procedure to find the area of a triangle when the vertices in the coordinate plane is known. Let us assume a triangle PQR, whose coordinates P, Q, and R are given as (x 1, y 1 ), (x 2, y 2 ), (x 3, y 3 ), respectively.

What is the area of a triangle ABC?

Therefore, the area of a triangle ABC is 9/2 square units. To know more about coordinate geometry and areas of polygons in a coordinate plane, log onto www.byjus.com. To watch interesting videos on the topic, download BYJU’S – The Learning App from Google Play Store.

What are the three rows of the determinant of the triangle?

Now, the three rows of the determinant of the given triangle are: [1 2 1], [4 0 1] and [-3 0 1]. The value of this determinat is -14, while its absolute value is 14.