How do you find the pressure in adiabatic process?

Solution

1. For an adiabatic compression we have p2=p1(V1V2)γ, so after the compression, the pressure of the mixture is p2=(1.00×105N/m2)(240×10−6m340×10−6m3)1.40=1.23×106N/m2.
2. The work done by the mixture during the compression is W=∫V2V1pdV. With the adiabatic condition of Equation 3.7.

What is the adiabatic process explain the work is done by the gas of the adiabatic thermodynamics?

For an adiabatic free expansion of an ideal gas, the gas is contained in an insulated container and then allowed to expand in a vacuum. Because there is no external pressure for the gas to expand against, the work done by or on the system is zero.

How is adiabatic constant calculated?

The ratio of CP to CV (CP/CV) for a gas is known as the specific heat ratio or adiabatic index and usually denoted by the Greek letter gamma ( ). For an ideal monoatomic gas (e.g. Helium, Argon etc), the adiabatic index is 5/3 or 1.67. For monoatomic gases, CV = 3R/2 and CP = 5R/2 (where R is universal gas constant).

How do you find the temperature of adiabatic process?

According to the definition of an adiabatic process, ΔU=wad. Therefore, ΔU = -96.7 J. Calculate the final temperature, the work done, and the change in internal energy when 0.0400 moles of CO at 25.0oC undergoes a reversible adiabatic expansion from 200.

How do you derive adiabatic equations?

The work done in adiabatic process derivation can be derived from the first law of thermodynamics relating to the change in internal energy dU to the work dW done by the system and the heat dQ added to it. The word done dW for the change in volume V by dV is given as PdV.

What is the condition for adiabatic process?

Essential conditions for the adiabatic process to take place are: i) System is perfectly insulated from surrounding. ii) The process must be carried out rapidly so that the system hs sufficient time to exchange heat with the surroundings.

How does Gamma change with temperature?

As temperature increases, higher-energy rotational and vibrational states become accessible to molecular gases, thus increasing the number of degrees of freedom and lowering γ. Thus, the ratio of the two values, γ, decreases with increasing temperature.