How many ways are there to divide 50 peoples into 3 groups so that each group contains members equal to a prime number?

The answer is equal to the number of solutions of a+b+c+d=24 with a,b,c,d>=0. But this is just 27 choose 3 = 2925.

How many different ways can a group of 6 people be divided into 2 teams of 3 people each?

6*5*4*3*2*1=720. The second idea is that the quantity “a choose b” is the number of ways to choose b individuals from a group of “a” individuals where a>0, b>=0 and a>=b.

How many ways can you divide 10 people into 5 groups?

Now, if the teams are unlabeled, we have to divide the answer by 5! =120 as each of the permutation is the same. So, required answer =113400120=945.

How many ways can 5 people be divided into three groups?

Here, the 5 people either be put in one group of 3 people then two groups with 1 person, or two groups with 2 people then one group of 1 person. Hence, 5 people can be divided into three groups in 25 ways. Was this answer helpful?

How many people can be in a group of 2?

There would be 15 groups, each with 2 members. If each person is equally likely to be in any group of a random size, then the answer is 30! (Astronomically big number). Considering that there are 15 total groups of 2, we need to specify. Which amount of the groups would actually be possible. We can show this as 2!+15!

How many ways in which 4 people can be chosen?

There are 4 × 3 × 2 ×1 ways in which 4 people can be chosen. 9 × 8 × 7 × 6 × 5 4 × 3 × 2 × 1 = 126 different committees.

How many ways can you divide 8 people into 4 teams?

In the process described above, every possible way of dividing 8 people into 4 teams of 2 people each has been counted 4! = 24 times. So the number of ways of dividing a group of 8 people into 4 teams of 2 people each = 28 * 15 * 6 / 24