Trendy

Is ch3o electron withdrawing?

Is ch3o electron withdrawing?

Yes, OCH3 which belongs to the is the electron-withdrawing group (methoxy group). Here, the oxygen (in OCH3) is more electronegative than carbon due to which it will show -I effect which is electron-withdrawing.

Is OCH3 Ortho para directing?

Both –OCH3 and –Ph are activating, ortho-/para-directing groups.

Which is more electron donating OCH3 or Oh?

OCH3 group is more electron withdrawing (i.e, shows more -I effect) than the OH group. Explanation: The reason is that, there are two lone pairs of oxygen. Oxygen has a smaller size, so in case of OCH3, the methyl group is close to the lone pair electrons, which leads to Steric repulsion.

What group is OCH3?

methoxy group
b) -OCH3 (methoxy group) The methoxy group is electron withdrawing by the inductive effect of the oxygen atom, since the electronegativity of oxygen is 2.6.

How is methoxy an electron donating group?

The oxygen atom does indeed exert an electron-withdrawing inductive effect, but the lone pairs on the oxygen cause the exact opposite effect – the methoxy group is an electron-donating group by resonance.

READ ALSO:   How do you measure the effectiveness of soft skills training?

Which pair of group contain both ortho and para directing group?

Thus, the methyl group is an ortho, para directing group.

Which is more electron donating group CH3 or OCH3?

Due to +R effect of -OCH3 group which arises due to the lone pair of oxygen atom,it become more electron donating group than -CH3 group where only +Ieffect is present.

What functional group is OCH3?

Methoxy (methoxy group; MeO): A molecular structure equivalent to methanol minus the OH group hydrogen atom: -OCH3.

Is OCH3 a functional group?

A methoxy group is the functional group consisting of a methyl group bound to oxygen. This alkoxy group has the formula O–CH3. On a benzene ring, the Hammett equation classifies a methoxy substituent at the para position as an electron-donating group, but as an electron-withdrawing group if at the meta position.