What is the minimum coefficient of static friction?

0.21
The minimum coefficient of static friction can be obtained from this equation: If the velocity of the car is 72 km/hr (20 m/s) and the radius of curvature R = 190 m, the minimum value of the coefficient of static friction is 0.21.

How do you find the minimum coefficient of static friction between two objects?

To find the minimum coefficient of static friction between two materials, construct an incline plane from one of the materials and place a body made from the other material on it. Increase the angle of the incline until the body starts to slide. The tangent of the angle is the coefficient of friction.

What is the minimum value of mu for no slipping of the two blocks on the surface?

The minimum value of u between the two blocks for no slipping is 2m Smooth mg 3mg (c) 2F 3mg ( 3mg 16.

What is the minimum coefficient of static friction needed to hold the car on the road?

The minimum friction coefficient required is 0.4 .

How do you find the minimum coefficient of static friction in circular motion?

The centripetal force causing the car to turn in a circular path is due to friction between the tires and the road. A minimum coefficient of friction is needed, or the car will move in a larger-radius curve and leave the roadway. We know that Fc=mv2r. Thus Fc=mv2r=(900.0kg)(25.00m/s)2(500.0m)=1125N.

What should be the minimum value of F?

0
Thus, on the boundary, the minimum value of f is 0 and the maximum is 9. In step 3 we compare these values with the value f(1, 1) = 1 at the critical point and conclude that the absolute maximum value of f on D is f(3, 0) = 9 and the absolute minimum value is f(0, 0) = f(2, 2) = 0.

What if the coefficient of static friction is 1?

A value of 1 means the frictional force is equal to the normal force. It is a misconception that the coefficient of friction is limited to values between zero and one. A coefficient of friction that is more than one just means that the frictional force is stronger than the normal force.

What should be the value of f to avoid slipping?

from the free body diagram given for block-A, we get the no slip condition for block-A is ( mA × a )< f , where f is frictional force between the surfaces of A and B. Hence if the applied force F is less than 176.4 N, there will not be any slip between blocks.