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What is the radius of the circle inscribed in an equilateral triangle ABC of sides 4 cms?

What is the radius of the circle inscribed in an equilateral triangle ABC of sides 4 cms?

Join OA, OB and OC. Let the radius of the circle be r cm. Therefore, the radius of the inscribed circle is 3.46 cm.

Can a circle be equilateral?

Yes. If you’re familiar with construction using compass and straight edge, one of the easiest ways to construct an equilateral triangle is to draw two circles where each circle’s centre lies on the other circle’s edge.

Where is the radius in a circle equation?

The center-radius form of the circle equation is in the format (x – h)2 + (y – k)2 = r2, with the center being at the point (h, k) and the radius being “r”. This form of the equation is helpful, since you can easily find the center and the radius.

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Where is the radius of a circle?

A radius is a straight line from the center of a circle to the circumference of a circle. If you have two or more of them, they are referred to as radii. All radii in a circle will be the same length.

Which triangle is inscribed in a circle of radius 6 cm?

An equilateral triangle is inscribed in a circle of radius 6 cm. Find its side.

How do you find the mid point of an equilateral triangle?

An equilateral triangle is inscribed in a circle of radius 6 cm. Find its side. Let ABC be an equilateral triangle inscribed in a circle of radius 6 cm . Let O be the centre of the circle . Then , Let OD be perpendicular from O on side BC . Then , D is the mid – point of BC.

Where does the centroid of an equilateral triangle lie?

The centroid of an equilateral triangle lies on the medians, which are also perpendicular to the bases, and splits the medians into two segments measuring ⅓ of the length and ⅔ of the length, respectively.

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How do you show that δbod is a 30-60-90 triangle?

The circle is inscribed in the triangle, so the two radii, OE and OD, are perpendicular to the sides of the triangle (AB and BC), and are equal to each other. BE=BD, using the Two Tangent theorem. BEOD is thus a kite, and we can use the kite properties to show that ΔBOD is a 30-60-90 triangle.