What mass of oxygen is required to react completely burn 1 mole of methane?
Table of Contents
- 1 What mass of oxygen is required to react completely burn 1 mole of methane?
- 2 What is the mass of oxygen required to react completely?
- 3 How many moles of oxygen gas react when a mole of methane undergoes complete combustion?
- 4 What is the mass of O2 required for the complete combustion of 4.8 kg of CH4?
- 5 What is the mass of the oxygen required to react completely with 15 gram of h2 gas to form water?
- 6 How many grams of oxygen will be required to react completely with 27?
- 7 How many grams of oxygen are required to completely react with 0.200 g of hydrogen to yield water also calculate the amount of water formed?
- 8 What mass of O2 in grams is required for complete combustion of 25.5 g of methane?
What mass of oxygen is required to react completely burn 1 mole of methane?
∴ 1 mole of methane requires 2 moles of oxygen for complete combustion.
What is the mass of oxygen required to react completely?
Thus, 24 g of oxygen gas would be required to react completely with 3 g of hydrogen gas.
How many moles of oxygen gas react when a mole of methane undergoes complete combustion?
How many moles of oxygen gas react when a mole of methane undergoes complete combustion? Do not include units in your answer. Thus, 2 mol of oxygen gas reacts with 1 mol of methane (CH4).
How many grams of oxygen are needed to completely react with 22.8 g of methane?
22.8⋅g16.01⋅g⋅mol−1=1.425⋅mol ..with respect to methane….
When 80 gm CH4 is burnt completely?
when 80 gm of CH4 is burnt completely, CO and CO2 gases are formed in 1:4 mole ratio.
What is the mass of O2 required for the complete combustion of 4.8 kg of CH4?
1/4 mole of CH4 will requires = 1/4 ×2 moles of O2 = 0.5 mol of O2 for complete combustion. So 11.2 L of O2 is required for complete combustion of 4 g CH4.
What is the mass of the oxygen required to react completely with 15 gram of h2 gas to form water?
15g Hydrogen takes up 324×15 =120g oxygen.
How many grams of oxygen will be required to react completely with 27?
According to avogadro’s law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro’s number of particles. Thus 48 grams of oxygen will be required to react completely with 27 gram of Al.
How many moles of oxygen will be completely oxidize 4 moles of CH4?
Explanation: The equation above is stoichiometrically balanced, and represents the combustion of 4 mol methane to give 4 mol carbon dioxide and 8 mol of water. 8 mol of dioxygen gas are required for complete combustion.
How many moles of O2 is required in the combustion reaction of methane CH4?
When you burn 6.25 moles of methane, you need 12.5 moles of oxygen gas.
How many grams of oxygen are required to completely react with 0.200 g of hydrogen to yield water also calculate the amount of water formed?
How many gram of oxygen (O_(2)) is required to completely react with 0.200 g of hydrogen (H_(2)) to yield water (H_(2)O)? Also calculate the amount of water formed (molecular mass H = 2, O = 32). 0.200 g of H2 produce H2O=364×0.200=1.8g.
What mass of O2 in grams is required for complete combustion of 25.5 g of methane?
102 grams
The mass of oxygen gas needed for the complete combustion of 25.5 grams of methane is 102 grams.